2y^4-18y^2+81=0

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Solution for 2y^4-18y^2+81=0 equation:


Simplifying
2y4 + -18y2 + 81 = 0

Reorder the terms:
81 + -18y2 + 2y4 = 0

Solving
81 + -18y2 + 2y4 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
40.5 + -9y2 + y4 = 0

Move the constant term to the right:

Add '-40.5' to each side of the equation.
40.5 + -9y2 + -40.5 + y4 = 0 + -40.5

Reorder the terms:
40.5 + -40.5 + -9y2 + y4 = 0 + -40.5

Combine like terms: 40.5 + -40.5 = 0.0
0.0 + -9y2 + y4 = 0 + -40.5
-9y2 + y4 = 0 + -40.5

Combine like terms: 0 + -40.5 = -40.5
-9y2 + y4 = -40.5

The y term is -9y2.  Take half its coefficient (-4.5).
Square it (20.25) and add it to both sides.

Add '20.25' to each side of the equation.
-9y2 + 20.25 + y4 = -40.5 + 20.25

Reorder the terms:
20.25 + -9y2 + y4 = -40.5 + 20.25

Combine like terms: -40.5 + 20.25 = -20.25
20.25 + -9y2 + y4 = -20.25

Factor a perfect square on the left side:
(y2 + -4.5)(y2 + -4.5) = -20.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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